Maximum Frequency of an Element After Performing Operations II

You are given an integer array `nums` and two integers `k` and `numOperations`. You must perform an **operation** `numOperations` times on `nums`, where in each operation you: - Select an index `i` that was **not** selected in any previous operations. - Add an integer in the range `[-k, k]` to `nums[i]`. Return the **maximum** possible frequency of any element in `nums` after performing the **operations**.   **Example 1:** **Input:** nums = [1,4,5], k = 1, numOperations = 2 **Output:** 2 **Explanation:** We can achieve a maximum frequency of two by: - Adding 0 to `nums[1]`, after which `nums` becomes `[1, 4, 5]`. - Adding -1 to `nums[2]`, after which `nums` becomes `[1, 4, 4]`. **Example 2:** **Input:** nums = [5,11,20,20], k = 5, numOperations = 1 **Output:** 2 **Explanation:** We can achieve a maximum frequency of two by: - Adding 0 to `nums[1]`.   **Constraints:** - `1 <= nums.length <= 105` - `1 <= nums[i] <= 109` - `0 <= k <= 109` - `0 <= numOperations <= nums.length`