Take Gifts From the Richest Pile
Difficulty: Easy
Category: DSA
Topics: Array, Heap (Priority Queue), Simulation
You are given an integer array `gifts` denoting the number of gifts in various piles. Every second, you do the following:
- Choose the pile with the maximum number of gifts.
- If there is more than one pile with the maximum number of gifts, choose any.
- Reduce the number of gifts in the pile to the floor of the square root of the original number of gifts in the pile.
Return _the number of gifts remaining after _`k`_ seconds._
**Example 1:**
**Input:** gifts = [25,64,9,4,100], k = 4
**Output:** 29
**Explanation:**
The gifts are taken in the following way:
- In the first second, the last pile is chosen and 10 gifts are left behind.
- Then the second pile is chosen and 8 gifts are left behind.
- After that the first pile is chosen and 5 gifts are left behind.
- Finally, the last pile is chosen again and 3 gifts are left behind.
The final remaining gifts are [5,8,9,4,3], so the total number of gifts remaining is 29.
```
**Example 2:**
**Input:** gifts = [1,1,1,1], k = 4
**Output:** 4
**Explanation:**
In this case, regardless which pile you choose, you have to leave behind 1 gift in each pile.
That is, you can't take any pile with you.
So, the total gifts remaining are 4.
```
**Constraints:**
- `1 <= gifts.length <= 103`
- `1 <= gifts[i] <= 109`
- `1 <= k <= 103`