Two Sum II - Input Array Is Sorted
Difficulty: Medium
Category: DSA
Topics: Array, Two Pointers, Binary Search
Given a **1-indexed** array of integers `numbers` that is already **_sorted in non-decreasing order_**, find two numbers such that they add up to a specific `target` number. Let these two numbers be `numbers[index1]` and `numbers[index2]` where `1 <= index1 < index2 <= numbers.length`.
Return_ the indices of the two numbers, _`index1`_ and _`index2`_, **added by one** as an integer array _`[index1, index2]`_ of length 2._
The tests are generated such that there is **exactly one solution**. You **may not** use the same element twice.
Your solution must use only constant extra space.
**Example 1:**
**Input:** numbers = [2,7,11,15], target = 9
**Output:** [1,2]
**Explanation:** The sum of 2 and 7 is 9. Therefore, index1 = 1, index2 = 2. We return [1, 2].
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**Example 2:**
**Input:** numbers = [2,3,4], target = 6
**Output:** [1,3]
**Explanation:** The sum of 2 and 4 is 6. Therefore index1 = 1, index2 = 3. We return [1, 3].
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**Example 3:**
**Input:** numbers = [-1,0], target = -1
**Output:** [1,2]
**Explanation:** The sum of -1 and 0 is -1. Therefore index1 = 1, index2 = 2. We return [1, 2].
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**Constraints:**
- `2 <= numbers.length <= 3 * 104`
- `-1000 <= numbers[i] <= 1000`
- `numbers` is sorted in **non-decreasing order**.
- `-1000 <= target <= 1000`
- The tests are generated such that there is **exactly one solution**.