Accounts Merge
Accounts Merge is a Medium Data Structures and Algorithms interview problem you can solve, run and submit on Thita.ai. It belongs to the Graph Traversal Patterns (DFS & BFS) pattern, in the Union-Find (Disjoint Set Union - DSU) subpattern.
Problem statement
Given a list of accounts where each element accounts[i] is a list of strings, where the first element accounts[i][0] is a name, and the rest of the elements are emails representing emails of the account.
Now, we would like to merge these accounts. Two accounts definitely belong to the same person if there is some common email to both accounts. Note that even if two accounts have the same name, they may belong to different people as people could have the same name. A person can have any number of accounts initially, but all of their accounts definitely have the same name.
After merging the accounts, return the accounts in the following format: the first element of each account is the name, and the rest of the elements are emails in sorted order. The accounts themselves can be returned in any order.
Example 1:
Input: accounts = [["John","johnsmith@mail.com","johnnewyork@mail.com"],["John","johnsmith@mail.com","john00@mail.com"],["Mary","mary@mail.com"],["John","johnnybravo@mail.com"]] Output: [["John","john00@mail.com","johnnewyork@mail.com","johnsmith@mail.com"],["Mary","mary@mail.com"],["John","johnnybravo@mail.com"]] Explanation: The first and second John's are the same person as they have the common email "johnsmith@mail.com". The third John and Mary are different people as none of their email addresses are used by other accounts. We could return these lists in any order, for example the answer [['Mary', 'mary@mail.com'], ['John', 'johnnybravo@mail.com'], ['John', 'john00@mail.com', 'johnnewyork@mail.com', 'johnsmith@mail.com']] would still be accepted.
Example 2:
Input: accounts = [["Gabe","Gabe0@m.co","Gabe3@m.co","Gabe1@m.co"],["Kevin","Kevin3@m.co","Kevin5@m.co","Kevin0@m.co"],["Ethan","Ethan5@m.co","Ethan4@m.co","Ethan0@m.co"],["Hanzo","Hanzo3@m.co","Hanzo1@m.co","Hanzo0@m.co"],["Fern","Fern5@m.co","Fern1@m.co","Fern0@m.co"]] Output: [["Ethan","Ethan0@m.co","Ethan4@m.co","Ethan5@m.co"],["Gabe","Gabe0@m.co","Gabe1@m.co","Gabe3@m.co"],["Hanzo","Hanzo0@m.co","Hanzo1@m.co","Hanzo3@m.co"],["Kevin","Kevin0@m.co","Kevin3@m.co","Kevin5@m.co"],["Fern","Fern0@m.co","Fern1@m.co","Fern5@m.co"]]
Constraints:
- 1 <= accounts.length <= 1000
- 2 <= accounts[i].length <= 10
- 1 <= accounts[i][j].length <= 30
- accounts[i][0] consists of English letters.
- accounts[i][j] (for j > 0) is a valid email.
Topics and companies
Topics: Array, Hash Table, String, Depth-First Search, Breadth-First Search, Union Find, Sorting.
Reported in interviews at Facebook, Google, Amazon, Microsoft, Twitter, LinkedIn.
How to practise Accounts Merge on Thita.ai
Starter code is provided in C, C#, C++, Go, Java, JavaScript and Python. Your solution runs against 5 test cases for this problem, with the AI coach available for a hint when you are stuck rather than a finished answer. The reference solution runs in O(N * K * log K), where N is the number of accounts and K is the maximum number of emails per account. Assigning ids and union operations are O(N*K). Grouping and sorting emails for each group is O(M log M) where M is the number of emails in a group, but since emails are inserted into a set, the total is O(T log T) where T is the total number of emails. time and O(T), where T is the total number of unique emails. We store mappings for each email and the union-find parent array. space.
Open Accounts Merge in the code editor, or read the Accounts Merge editorial for a worked solution with its approach and complexity analysis.
Where Accounts Merge sits in the DSA pattern sheet
- Graph Traversal Patterns (DFS & BFS) pattern guide
- Union-Find (Disjoint Set Union - DSU) subpattern
- The full DSA patterns sheet
- All coding practice problems
Problems related to Accounts Merge
Other problems that use the same Union-Find (Disjoint Set Union - DSU) and Graph Traversal Patterns (DFS & BFS) techniques:
- Graph Valid Tree — Medium, same subpattern
- Largest Component Size by Common Factor — Hard, same subpattern
- Most Stones Removed with Same Row or Column — Medium, same subpattern
- Number of Connected Components in an Undirected Graph — Medium, same subpattern
- Number of Islands II — Hard, same subpattern
- Redundant Connection — Medium, same subpattern